2009. 7. 7 1/3 semiconductor technical data KCR402T constant-current led driver transistor revision no : 0 led drive application. features supplies stable bias current even at low battery voltage. ideal for stabilizing bias current of leds. negative temperature coefficient protects leds against thermal overload. 1. gnd 2. output current 3. output current 4. source voltage 5. output current 6. rext dim millimeters a b d e ts6 2.9 0.2 1.6+0.2/-0.1 0.70 0.05 0.4 0.1 2.8+0.2/-0.3 1.9 0.2 0.95 0.16 0.05 0.00-0.10 0.25+0.25/-0.15 c f g h i j k0.60 l0.55 a f g g d k k b e c l h j j i 2 3 5 16 4 + _ + _ + _ + _ + _ equivalent circuit maximum rating (ta=25 ) marking 654 123 characteristic symbol rating unit source voltage v s 40 v output current i o 65 ma output voltage v o 38 v reverse voltage between all terminals v r 0.5 v power dissipation p d * 900 mw junction temperature t j 150 storage temperature range t stg -55 150 type name aa 654 123 lot no. *package mounted on a ceramic board (600 ?? 0.8 ? )
2009. 7. 7 2/3 KCR402T revision no : 0 electrical characteristics (ta=25 ) characteristic symbol test condition min. typ. max. unit collector-emitter breakdown voltage bv ceo i c =1ma, i b =0 40 - - v supply current i s v s =10v 340 420 500 ? dc current gain h fe i c =50ma, v ce =1v 100 220 470 - internal resistor r int i rint =20ma 37 44 53 ? output current i o v s =10v, v out =8.6v 18 20 22 ma voltage drop (v s -v e ) v drop i o =20ma 0.8 0.85 0.9 v lowest sufficient battery voltage overhead v smin i o >18ma - 1.4 - v output current change versus ta ? i o /i o v s =10v - -0.2 - %/k output current change versus v s ? i o /i o v s =10v - 1 - %/v application circuit 1 2, 3, 5 led led 6 4 +v s rex t
2009. 7. 7 3/3 KCR402T revision no : 0 18 ohm 27 ohm 36 ohm 82 ohm open source voltage v s (v) i o - v s output current i o (ma) 0 5 10 15 20 25 25 30 0510 15 20 45 50 40 35 v s -v o =1.2v,2v v s -v o =1v i s - v s -40 c 20 c 80 c -40 c 20 c 80 c -40 c 20 c 80 c source voltage v s (v) i o - v s output current i o (ma) 10 100 25 30 0510 15 20 45 50 40 35 v s -v o =1.4v source voltage v s (v) supply current i s (ma) 0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 25 30 051015 20 45 50 40 35 source voltage v s (v) i o - v s output current i o (ma) 10 100 25 30 0510 15 20 45 50 40 35 ta=25 c 10 100 external resistor rext ( ? ) i o - r ext output current i o (ma) 10 100 v s =10v v s -v o =1.4v v s -v o =1.4v
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